I greet you this day,
First: Review the Notes/Multimedia Resources/eText.
Second: View the Videos.
Third: Solve the questions/solved examples.
Fourth: Check your solutions with my thoroughly-explained solved examples.
Samuel Dominic Chukwuemeka (SamDom For Peace)
B.Eng., A.A.T, M.Ed., M.S
Students will:
(1.) Discuss the meaning of hypothesis testing.
(2.) Explain the meaning of null and alternative hypothesis.
(3.) State the null and alternative hypothesis from a given claim.
(4.) State the type of hypothesis test.
(5.) State the population parameter being tested.
(6.) Explain the meaning of Type I and Type II errors.
(7.) Discuss social injustice related to Type I and Type II errors. (Relate Statistics to Criminology).
(8.) Identify the Type I and Type II errors from a claim.
(9.) Identify the Type I and Type II errors in social cases. (Relate Statistics to Criminology).
(10.) Discuss the three methods used in hypothesis testing.
(11.) Test the hypothesis for a claim using the Critical Method (Classical Approach).
(12.) Test the hypothesis for a claim using the Probability Value Method (P-value Approach).
(13.) Test the hypothesis for a claim using the Confidence Interval Method.
(14.) Write the decision of the hypothesis test based on the methods used.
(15.) Write the conclusion of the hypothesis test based on the decision.
(16.) Interpret the conclusion.
(17.) Discuss the power of a hypothesis test.
A hypothesis test is a procedure for testing a claim about a population parameter.
The null hypothesis is the statement that shows that the value of the population parameter is equal to some claimed value.
It is always a statement about a population parameter.
The value in the null hypothesis is the value of the population parameter that represents the status-quo for the current situation.
It is denoted by $H_0$
We test the null hypothesis assuming it to be true thorughout the hypothesis testing procedure, unless observation strongly indicates otherwise.
We make a decision based on the null hypothesis.
We either reject the null the hypothesis; or we do not reject the null hypothesis (or fail to reject the null hypothesis)
based on the result of the methods we used for the test.
Fail to reject the null hypothesis is the same as Do not reject the null hypothesis.
This does not mean that we accept the null hypothesis. It just means that we do not reject it.
Explain this concept with examples.
Then, we make a conclusion based on our decision.
The alternative hypothesis is the statement that shows that the value of the population parameter is different from the claimed value.
(different from the claimed value could mean: less than the claimed value; more than the claimed value; or not equal to the claimed value.)
It is the research hypothesis.
It is denoted by $H_1$ or $H_A$ or $H_a$
The population parameter being different from the claimed value means that it could be less than the claimed value; or
greater than the claimed value; or not equal to the claimed value.
If the population parameter is less than the claimed value, the hypothesis test is a left-tailed test.
In left-tailed tests, the critical region is in the extreme left region (left tail).
$population\:\:parameter \lt claimed\:\:value \implies left-tailed\:\:test$
If the population parameter is greater than the claimed value, the hypothesis test is a right-tailed test.
In right-tailed tests, the critical region is in the extreme right region (right tail).
$population\:\:parameter \gt claimed\:\:value \implies right-tailed\:\:test$
Left-tailed tests and Right-tailed tests are one-tailed tests.
If the population parameter is not equal to the claimed value, the hypothesis test is a two-tailed test.
In two-tailed tests, the critical region is in the two extreme regions (two tails: left tail and right tail).
$population\:\:parameter \ne claimed\:\:value \implies two-tailed\:\:test$
The test statistic compares the observed outcome with the outcome of the null hypothesis.
It measures how far away the observed parameter lies from the hypothesized value of the population parameter.
It is used in making a decision about the null hypothesis.
It is found by converting the sample statistic to a score with the assumption that the null hypothesis is true.
A test statistic close to 0 indicates the obtained sample statistic is likely if the null hypothesis is correct, which supports the null hypothesis.
A test statistic far from 0 indicates the obtained sample statistic is unlikely if the null hypothesis is correct, which discredits the null hypothesis.
There are three methods used in hypothesis testing.
Two of those methods will always lead to the same decision, and ultimaltely the same conclusion.
Those are the two main methods.
The other method may be used only when those two main methods are used.
The two main methods are:
(1.) Critical Value Method or Classical Approach or Traditional Method
If the test statistic is in the critical region, reject the null hypothesis.
If the test statistic is not in the critical region, do not reject the null hypothesis.
The critical values define the critical regions.
For a left-tailed hypothesis test, any value less than the critical value in the left-tail is in the critical region.
For a right-tailed hypothesis test, any value greater than the critical value in the right-tail is in the critical region.
For a two-tailed hypothesis test, any values less than the critical value in the left-tail OR greater than the critical value in the right-tail is in the critical region.
(2.) P-Value Method or Probability Value Method
If the P-value is less than or equal to the level of significance, reject the null hypothesis.
If the P-value is greater than the level of significance, do not reject the null hypothesis.
The other method is:
(3.) Confidence Interval Method
Sometimes, we use the Confidence Interval method to test the hypothesis.
We typically use this method for: one sample with two tails; two samples with left tail; two samples with right tail; or two samples with two tails.
If the confidence interval does not contain the value of the population parameter stated in the null hypothesis, reject the null hypothesis.
If the confidence interval contains the value of the population parameter stated in the null hypothesis, do not reject the null hypothesis.
For one-tailed hypothesis test: construct a confidence interval using: $CL = 1 - 2\alpha$
For two-tailed hypothesis test: construct a confidence interval using: $CL = 1 - \alpha$
NOTE:
(I.) The Classical Approach and the P-value Approach will always give the same decision and the same conclusion regardless of the hypothesis test.
(II.) For Hypothesis test about a Population Proportion; the Confidence Interval Method may or may not give the same decison and the same conclusion as the other two methods.
Explain this concept with examples.
(III.) For Hypothesis test about a: Population Mean, Population Variance, and Population Standard Deviation; all three methods will always give the same decision and the same conclusion.
What if we formed our hypothesis correctly, applied the correct methods to test it, performed our calculation correctly, and
still made a wrong decision which leads to a wrong conclusion?
Is it possible?
YES. It is possible.
Why?
We are humans.
Humans are known for making mistakes.
This leads us to....
There are two main types of errors we can make when testing hypothesis.
They are:
Type I Error (Rejecting a true null hypothesis)
This is the error made when we reject the null hypothesis when it is true.
Compare it to a False Positive scenario in Probability (Questions 50 and 51). Explain.
It is also similar to convicting an innocent man
Type II Error (Not rejecting a false null hypothesis)
This is the error made when we fail to reject the null hypothesis when it is false.
Compare it to a False Negative scenario in Probability (Questions 49 and 52). Explain.
It is also similar to acquiting a guilty man
Both errors are bad.
However, which one do you think is worse?
Type I error OR Type II error?
Would you convict an innocent man? OR Would you acquit a guilty man?
Explain to students the extreme dangers of having anything to do with innocent blood.
To further explain these errors, let us review the table.
Truth | |||
$H_0$ is true | $H_0$ is false | ||
Decision | Reject $H_0$ | Type I error | Correct decision |
Do not reject $H_0$ | Correct decision | Type II error |
Compare this to: (You may use this to remember the main table)
Truth | |||
Innocent | Guilty | ||
Verdict | Convict | Type I error | Correct decision |
Acquit | Correct decision | Type II error |
$\alpha$ is the probability of making a Type I error.
$\beta$ is the probability of making a Type II error.
Type I and Type II errors are inversely related.
As $\alpha$ increases, $\beta$ decreases.
As $\alpha$ decreases, $\beta$ increases.
Ask students to define the level of significance (when we covered Inferential Statistics)
We are going to give another definition of the level of significance (as it concerns Hypothesis Testing).
The level of significance is the probability of making the mistake of rejecting the null hypothesis even though it is true.
This implies that: The level of significance is the probability of making a Type I error.
It is the likelihood of obtaining a sample statistic distinct from the predicted population parameter to the extent that it makes the predicted population parameter seem incorrect when, in fact, it is correct.
It is denoted by α.
Though the acceptable significance level depends on the situation, 5%(0.05) is generally a good starting point.
NOTE: If α is not given, use α = 5%
The probability value (p-value) is the probability that if the null hypothesis is true, a test statistic will have a value as extreme as or more extreme than the observed value.
In other words, the p-value measures how unusual an event is.
It is denoted by p.
A p-value lower than the significance level is small, and it discredits the null hypothesis.
A p-value greater than the significance level is not small, and it indicates that the null hypothesis is probably true.
A p-value is small if it is less than 0.05 (because the common significance level is 0.05).
The power of a hypothesis test is the probability of rejecting a null hypothesis when it is false.
This implies that: The power of a hypothesis test is the probability of making the correct decision by avoiding making a Type II error.
The power of a hypothesis test depends on the significance level, the sample size, and how wrong the null hypothesis is.
(1.) The samples are simple random samples.
(2.) There is a fixed number of trials.
(3.) The trials are independent.
(4.) Each trial results in either a success or a failure.
(5.) The probability of success or failure in any trial is the same as the probability of success or failure in all the trials.
(6.) There are at least ten successes and ten failures.
$np \ge 10$ AND $nq \ge 10$
(7.) The sample size is no more than five percent (at most five percent) of the population size.
$n \le 5\%N$ or $n \le 0.05N$
NOTE: If the population proportion is not given, use $50\%$
If $p$ is not given, use $p = 50\%$ or $p = 0.5$
(1.) The sample proportions are from two simple random independent samples.
Independent samples means that the sample values selected from one population proportion are not related to, or
somehow natuarlly paired or matched with the sample values from the other population.
(2.) There are at least five successes and five failures for each of the two samples.
$n\hat{p} \ge 5$ AND $n\hat{q} \ge 5$ for each of the two samples.
The two main Hypothesis Test Methods uses the pooled sample proportion.
This means that the data is pooled (sort of like "pooling resources together") to obtain the proportion of successes
in both samples combined.
The Confidence Interval Method uses the unpooled sample proportions.
This means the two sample proportions are treated separately.
(1.) The samples are simple random samples.
(2.) The population is normally distributed, OR the sample size is greater than thirty ($n \gt 30$).
Two samples are independent if the sample values from one population are not related to, or somehow naturally
paired or matched with the sample values from the other population.
Example: Paul was curious about the mean credit scores of men and women.
He visited the Town of Okay, Oklahoma and gathered two random samples: the credit scores
of 50 men and 50 women.
Two samples are dependent if the sample values from one population are related to, or somehow naturally
paired or matched with the sample values from the other population.
Each pair of sample values consists of two measurements from the same subject (such as before/after data), or
each pair of sample values consists of matched pairs (such as husband/wife data).
Example: Paul was curious about the mean credit scores of married couples.
He visited the Community of Money, Mississippi, randomly selected 50 families, and asked for each of the credit
scores of the husband and wife.
When $\sigma_1$ and $\sigma_2$ are unknown, and are not assumed to be equal: AND
When $\mu_1$ and $\mu_2$ are assumed to be equal:
Use $t$ distribution
(1.) The values of the first population standard deviation and the second population standard deviation are unknown,
and are not assumed to be equal.
(2.) The two samples are simple random samples.
(3.) The two samples are independent.
(4.) The two samples are taken from a normally distributed population, or each of the samples have sizes greater than $30$.
When $\sigma_1$ and $\sigma_2$ are unknown, but assumed to be equal:
Use $t$ distribution and a pooled sample variance
(1.) The values of the first population standard deviation and the second population standard deviation are unknown,
but they are assumed to be equal.
(2.) The two samples are simple random samples.
(3.) The two samples are independent.
(4.) The two samples are taken from a normally distributed population, or each of the samples have sizes greater than $30$.
When $\sigma_1$ and $\sigma_2$ are known:
Use $z$ distribution
(1.) The values of the first population standard deviation and the second population standard deviation are known.
(2.) The two samples are simple random samples.
(3.) The two samples are independent.
(4.) The two samples are taken from a normally distributed population, or each of the samples have sizes greater than $30$.
Use $t$ distribution for Dependent Samples
(1.) The samples are dependent samples (matched pairs).
(2.) The two samples are simple random samples.
(3.) The two samples are taken from a normally distributed population, or each of the samples have sizes greater than 30.
Use $\chi^2$ distribution
(1.) The samples are simple random samples.
(2.) The population is normally distributed.
Proportion is given as a decimal or a percentage.
If the significance level, $\alpha$ is not given, use $\alpha = 5\%$
The null hypothesis should always have the 'equal' symbol
The alternative hypothesis has the 'unequal' symbol (less than, greater than, not equal to)
To calculate the probability of making a Type II error, $\beta$
As applicable:
First Step:
Solve for the critical proportion using the critical $z$ OR
Solve for the critical mean using the critical $z$ OR
Solve for the critical mean using the critical $t$
$
(1.)\:\: z_{\dfrac{\alpha}{2}} = \dfrac{\hat{p_c} - p}{\sqrt{\dfrac{pq}{n}}} \\[10ex]
(2.)\:\: \hat{p_c} = z_{\dfrac{\alpha}{2}} * \sqrt{\dfrac{pq}{n}} + p \\[7ex]
(3.)\:\: z_{\dfrac{\alpha}{2}} = \dfrac{\overline{x}_c - \mu}{\dfrac{\sigma}{\sqrt{n}}} \\[10ex]
(4.)\:\: \overline{x_c} = z_{\dfrac{\alpha}{2}} * \dfrac{\sigma}{\sqrt{n}} + \mu \\[7ex]
(5.)\:\: t_{\dfrac{\alpha}{2}} = \dfrac{\overline{x}_c - \mu}{\dfrac{s}{\sqrt{n}}} \\[10ex]
(6.)\:\: \overline{x_c} = t_{\dfrac{\alpha}{2}} * \dfrac{s}{\sqrt{n}} + \mu \\[7ex]
$
Second Step:
Solve for the $z$ score using the alternative proportion OR
Solve for the $z$ score using the alternative mean OR
Solve for the $t$ score using the alternative mean
$
(7.)\:\: z = \dfrac{\hat{p_c} - p_a}{\sqrt{\dfrac{p_a * q_a}{n}}} \\[10ex]
(8.)\:\: z = \dfrac{\overline{x}_a - \mu}{\dfrac{\sigma}{\sqrt{n}}} \\[10ex]
(9.)\:\: t = \dfrac{\overline{x}_a - \mu}{\dfrac{s}{\sqrt{n}}} \\[10ex]
$
Third Step:
Calculate the probability of $z$ OR
Calculate the probability of $t$
$ (1.)\:\: P_{hyp} = 1 - \beta \\[3ex] $
If $p$ is not given, use $p = 50\%$
$ (1.)\:\: \hat{p} = \dfrac{x}{n} \\[7ex] (2.)\:\: p + q = 1 \\[5ex] (3.)\:\: z = \dfrac{\hat{p} - p}{\sqrt{\dfrac{pq}{n}}} \\[10ex] $
The pooled sample proportion is used.
This means that the data is pooled to obtain the proportion of successess in both samples combined
rather than separately (unpooled).
$ (1.)\:\: \hat{p_1} = \dfrac{x_1}{n_1} \\[7ex] (2.)\:\: \hat{p_2} = \dfrac{x_2}{n_2} \\[7ex] (3.)\:\: \overline{p} = \dfrac{x_1 + x_2}{n_1 + n_2} \\[7ex] (4.)\:\: \overline{q} = 1 - \overline{p} \\[5ex] (5.)\:\: z = \dfrac{(\hat{p_1} - \hat{p_2}) - (p_1 - p_2)}{\sqrt{\dfrac{\overline{p} * \overline{q}}{n_1} + \dfrac{\overline{p} * \overline{q}}{n_2}}} \\[10ex] $
Because this is a pooled sample, we assume the null hypothesis as:
$
H_0:\:\: p_1 = p_2 \:\:OR \\[3ex]
H_0:\:\: p_1 - p_2 = 0 \\[3ex]
\implies \\[3ex]
(6.)\:\: z = \dfrac{\hat{p_1} - \hat{p_2}}{\sqrt{\dfrac{\overline{p} * \overline{q}}{n_1} +
\dfrac{\overline{p} * \overline{q}}{n_2}}} \\[10ex]
(7.)\:\: SE = \sqrt{\dfrac{\overline{p} * \overline{q}}{n_1} + \dfrac{\overline{p} *
\overline{q}}{n_2}} \\[7ex]
$
The unpooled sample proportion is used.
This means that the two sample proportions are treated separately.
$
(1.)\:\: E = z_{\dfrac{\alpha}{2}} * \sqrt{\dfrac{\hat{p_1} * \hat{q_1}}{n_1} + \dfrac{\hat{p_2} *
\hat{q_2}}{n_2}} \\[7ex]
$
The confidence interval method of the difference of the population proportions is:
$(\hat{p_1} - \hat{p_2}) - E \lt (p_1 - p_2) \lt (\hat{p_1} - \hat{p_2}) + E \\[3ex]$
When $\sigma$ is known:
$
(1.)\:\: z = \dfrac{\overline{x} - \mu}{\dfrac{\sigma}{\sqrt{n}}} \\[10ex]
$
When $\sigma$ is NOT known:
$
(2.)\:\: t = \dfrac{\bar{x} - \mu}{\dfrac{s}{\sqrt{n}}} \\[10ex]
(3.)\:\: df = n - 1 \\[3ex]
$
Two samples are independent if the sample values from one population are not related to, or natuarlly paired or paired with the sample values from the other population.
When t distribution is used
When $\sigma_1$ and $\sigma_2$ are unknown; and are NOT assumed to be equal
$
(1.)\:\: t = \dfrac{(\overline{x_1} - \overline{x_2}) - (\mu_1 - \mu_2)}{\sqrt{\dfrac{s_1^2}{n_1} +
\dfrac{s_2^2}{n_2}}} \\[10ex]
$
When $\mu_1 - \mu_2$ is assumed to be $0$:
$
(2.)\:\: t = \dfrac{\overline{x_1} - \overline{x_2}}{\sqrt{\dfrac{s_1^2}{n_1} + \dfrac{s_2^2}{n_2}}}
\\[10ex]
$
Simple Estimate of the Degrees of Freedom:
$
(3.)\:\: df = the\:\:smaller\:\:value\:\:of\:\:(n_1 - 1) \:\:and\:\: (n_2 - 1) \\[3ex]
$
Difficult Estimate (More Accurate Estimate) of the Degrees of Freedom:
$
(4.)\:\: df = \dfrac{(A + B)^2}{\dfrac{A^2}{n_1 - 1} + \dfrac{B^2}{n_2 - 1}} \\[10ex]
(5.)\:\: A = \dfrac{s_1^2}{n_1} \\[7ex]
(6.)\:\: B = \dfrac{s_2^2}{n_2} \\[7ex]
$
When t distribution is used
When $\sigma_1$ and $\sigma_2$ are unknown; and are assumed to be equal
The pooled dample variance is used.
$
(1.)\:\: t = \dfrac{(\overline{x_1} - \overline{x_2}) - (\mu_1 - \mu_2)}{\sqrt{\dfrac{s_p^2}{n_1} +
\dfrac{s_p^2}{n_2}}} \\[10ex]
(2.)\:\: s_p^2 = \dfrac{s_1^2(n_1 - 1) + s_2^2(n_2 - 1)}{(n_1 - 1)(n_2 - 1)} \\[7ex]
(3.)\:\: s_p = \sqrt{\dfrac{s_1^2(n_1 - 1) + s_2^2(n_2 - 1)}{(n_1 - 1)(n_2 - 1)}} \\[7ex]
(4.)\:\: df = n_1 + n_2 - 2 \\[3ex]
$
When $z$ distribution is used
When $\sigma_1$ and $\sigma_2$ are known
$
(1.)\:\: z = \dfrac{(\overline{x_1} - \overline{x_2}) - (\mu_1 -
\mu_2)}{\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}} \\[10ex]
$
When $\sigma_1$ and $\sigma_2$ are unknown; and are NOT assumed to be equal
The confidence interval method of the difference of the population means is:
$
(1.)\:\: Confidence\:\:Interval\:\:is:\:\:(\overline{x_1} - \overline{x_2}) - E \lt (\mu_1 - \mu_2)
\lt (\overline{x_1} - \overline{x_2}) + E \\[5ex]
(2.)\:\: E = t_{\dfrac{\alpha}{2}} * \sqrt{\dfrac{s_1^2}{n_1} + \dfrac{s_2^2}{n_2}} \\[7ex]
$
Simple Estimate of the Degrees of Freedom:
$
(3.)\:\: df = the\:\:smaller\:\:value\:\:of\:\:(n_1 - 1) \:\:and\:\: (n_2 - 1) \\[3ex]
$
Difficult Estimate (More Accurate Estimate) of the Degrees of Freedom:
$
(4.)\:\: df = \dfrac{(A + B)^2}{\dfrac{A^2}{n_1 - 1} + \dfrac{B^2}{n_2 - 1}} \\[10ex]
(5.)\:\: A = \dfrac{s_1^2}{n_1} \\[7ex]
(6.)\:\: B = \dfrac{s_2^2}{n_2} \\[7ex]
$
When $\sigma_1$ and $\sigma_2$ are unknown; and are NOT assumed to be equal
The confidence interval method of the difference of the population means is:
$
(1.)\:\: Confidence\:\:Interval\:\:is:\:\:(\overline{x_1} - \overline{x_2}) - E \lt (\mu_1 - \mu_2)
\lt (\overline{x_1} - \overline{x_2}) + E \\[5ex]
(2.)\:\: E = t_{\dfrac{\alpha}{2}} * \sqrt{\dfrac{s_p^2}{n_1} + \dfrac{s_p^2}{n_2}} \\[7ex]
(3.)\:\: s_p^2 = \dfrac{s_1^2(n_1 - 1) + s_2^2(n_2 - 1)}{(n_1 - 1)(n_2 - 1)} \\[7ex]
(4.)\:\: s_p = \sqrt{\dfrac{s_1^2(n_1 - 1) + s_2^2(n_2 - 1)}{(n_1 - 1)(n_2 - 1)}} \\[7ex]
(5.)\:\: df = n_1 + n_2 - 2 \\[3ex]
$
When $z$ distribution is used
When $\sigma_1$ and $\sigma_2$ are known
The confidence interval method of the difference of the population means is:
$
(1.)\:\: Confidence\:\:Interval\:\:is:\:\:(\overline{x_1} - \overline{x_2}) - E \lt (\mu_1 - \mu_2)
\lt (\overline{x_1} - \overline{x_2}) + E \\[5ex]
(2.)\:\: E = z_{\dfrac{\alpha}{2}} * \sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}
\\[7ex]
$
Two samples are dependent if the sample values are somehow matched, where the matching is
based on some meaningful
relationship.
Each pair of sample values consists of two measurements from the same subject (such as
before/after data), or each pair
of sample values consists of matched pairs (such as husband/wife data).
$
(1.)\:\: t = \dfrac{\overline{d} - \mu_d}{\dfrac{s_d}{\sqrt{n}}} \\[7ex]
(2.)\:\: df = n - 1 \\[3ex]
$
$ (1.)\:\: Confidence\:\:Interval\:\:is:\:\: \overline{d} - E \lt \mu_d \lt \overline{d} + E \\[5ex] (2.)\:\: E = t_{\dfrac{\alpha}{2}} * \dfrac{s_d}{\sqrt{n}} \\[5ex] $
Normally Distributed Population
$
(1.)\;\; \chi^2 = \dfrac{s^2(n - 1)}{\sigma^2} \\[5ex]
$
$ (1.)\:\: \chi^2 = \Sigma \dfrac{(O - E)^2}{E} \\[7ex] (2.)\:\: df = k - 1 \\[3ex] $
Two Samples
First Formula for the Pearson Correlation Coefficient
$
(1.)\:\: r = \dfrac{\Sigma \left(\dfrac{x - \overline{x}}{s_x}\right)\left(\dfrac{y -
\overline{y}}{s_y}\right)}{n - 1} \\[10ex]
(2.)\:\: r = \dfrac{\Sigma(z_x)(z_y)}{n - 1} \\[5ex]
$
Second Formula for the Pearson Correlation Coefficient
$
(1.)\:\: r = \dfrac{n(\Sigma xy) - (\Sigma x)(\Sigma y)}{\sqrt{n(\Sigma x^2) - (\Sigma x)^2} *
\sqrt{n(\Sigma y^2) - (\Sigma y)^2}} \\[7ex]
$
Critical Value of the Correlation Coefficient (Use for Critical Value method)
$
(1.)\:\: Critical\:\:value\:\:of\:\:r = \sqrt{\dfrac{t^2}{t^2 + df}} \\[7ex]
(where\:\:t-values\:\:are\:\:from\:\:the\:\:Critical\:\:t\:\:Table) \\[3ex]
(2.)\:\: df = n - 2 \\[3ex]
$
Test Statistic of the Correlation Coefficient (Use for P-value method)
$
(1.)\:\: t = \dfrac{r}{\sqrt{\dfrac{1 - r^2}{n - 2}}} \\[7ex]
$
NOTE:
(1.) Use $z$ or $t$ as necessary
(2.) For the interpretations, replace proportion with mean as applicable.
Unless your professor says otherwise:
(3.) Use only these terms for the Decision
(a.) Reject the null hypothesis
(b.) Do not reject the null hypothesis.
(c.) Fail to reject the null hypothesis.
(b.) and (c.) means the same thing.
Keep in mind that we are dealing with the null hypothesis
You either reject the null hypothesis or you do not reject the null hypothesis.
We do not accept the null hypothesis.
We just do not reject it.
The fact that we do not reject it does not mean that we accept it.
Hence, the need for the conclusion and the interpretation.
(4.) Use only these terms for the Conclusion
(a.) There is sufficient evidence to support/warrant the rejection of the null hypothesis.
(b.) There is sufficient evidence to reject the null hypothesis.
(c.) There is sufficient evidence to support/warrant the claim of the alternative hypothesis.
(d.) There is insufficient evidence to support/warrant the rejection of the null hypothesis.
(e.) There is insufficient evidence to reject the null hypothesis.
(f.) There is insufficient evidence to support/warrant the claim of the alternative hypothesis.
(a.), (b.), and (c.) means the same thing.
(d.), (e.), and (f.) means the same thing.
IMPORTANT:
(1.) For:
Hypothesis Test about a Population Proportion OR
Hypothesis Test about a Population Mean
Use $z$ table
(2.) For:
Hypothesis Test about a Population Mean (whose Population Standard Deviation is not known)
Use $t$ table
(3.) For:
Hypothesis Test about a Population Variance OR
Hypothesis Test about a Population Standard Deviation
use $\chi^2$ table
Find $-z_{\dfrac{\alpha}{2}}$
Condition $1$
If $z \lt -z_{\dfrac{\alpha}{2}}$, it falls in the critical region
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of the alternative hypothesis
Interpretation for One-Sample: The population proportion for the variable is significantly less than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is significantly less than the
population proportion for the second sample
Condition $2$
If $z \gt -z_{\dfrac{\alpha}{2}}$, it does not fall in the critical region
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of the alternative hypothesis
Interpretation for One-Sample: The population proportion for the variable is NOT significantly less than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is NOT significantly less than the
population proportion for the second sample
Find $z_{\dfrac{\alpha}{2}}$
Condition $1$
If $z \gt z_{\dfrac{\alpha}{2}}$, it falls in the critical region
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of the alternative hypothesis
Interpretation for One-Sample: The population proportion for the variable is significantly more than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is significantly more than the
population proportion for the second sample
Condition $2$
If $z \lt z_{\dfrac{\alpha}{2}}$, it does not fall in the critical region
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of the alternative hypothesis
Interpretation for One-Sample: The population proportion for the variable is NOT significantly more than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is NOT significantly more than the
population proportion for the second sample
Find $-z_{\dfrac{\alpha}{2}}$ and $z_{\dfrac{\alpha}{2}}$
Condition $1$
If $z \lt -z_{\dfrac{\alpha}{2}}$ OR $z \gt z_{\dfrac{\alpha}{2}}$, it falls in the critical region
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the rejection of the null hypothesis
Interpretation for One-Sample: The population proportion for the variable is significantly different than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is significantly different from the
population proportion for the second sample
Condition $2$
If $-z_{\dfrac{\alpha}{2}} \lt z \lt z_{\dfrac{\alpha}{2}}$, it does not fall in the critical region
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to warrant the rejection of the null hypothesis
Interpretation for One-Sample: The population proportion for the variable is NOT significantly different than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is NOT significantly different from the
population proportion for the second sample
Find $P(z \lt -test\:\:statistic)$
Condition $1$
If $P-value \le \alpha$
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of the alternative hypothesis
Interpretation for One-Sample: The population proportion for the variable is significantly less than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is significantly less than the
population proportion for the second sample
Condition $2$
If $P-value \gt \alpha$
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of the alternative hypothesis
Interpretation for One-Sample: The population proportion for the variable is NOT significantly less than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is NOT significantly less than the
population proportion for the second sample
Find $P(z \gt test\:\:statistic)$
Condition $1$
If $P-value \le \alpha$
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of the alternative hypothesis
Interpretation for One-Sample: The population proportion for the variable is significantly more than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is significantly more than the
population proportion for the second sample
Condition $2$
If $P-value \gt \alpha$
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of the alternative hypothesis
Interpretation for One-Sample: The population proportion for the variable is NOT significantly more than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is NOT significantly more than the
population proportion for the second sample
Find $P(z \lt -test\:\:statistic) + P(z \gt test\:\:statistic)$
Condition $1$
If $P-value \le \alpha$
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the rejection of the null hypothesis
Interpretation for One-Sample: The population proportion for the variable is significantly different than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is significantly different from the
population proportion for the second sample
Condition $2$
If $P-value \gt \alpha$
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to warrant the rejection of the null hypothesis
Interpretation for One-Sample: The population proportion for the variable is NOT significantly different than the stated value.
Interpretation for Two-Samples: The population proportion for the first sample is NOT significantly different from the
population proportion for the second sample
Construct a confidence interval using: $CL = 1 - 2\alpha$
Determine the confidence interval using an appropriate confidence level
Condition $1$
If the confidence interval does NOT the value of the population parameter stated in the null hypothesis:
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to warrant the rejection of the null hypothesis
Interpretation: The confidence interval does NOT contain the value of the population parameter stated in
the null hypothesis
Condition $2$
If the confidence interval contains the value of the population parameter stated in the null hypothesis:
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of the alternative hypothesis
Interpretation: The confidence interval contains the value of the population parameter stated in
the null hypothesis
Construct a confidence interval using: $CL = 1 - \alpha$
Determine the confidence interval using an appropriate confidence level
Condition $1$
If $Lower\:\:Confidence\:\:Limit \lt 0$ AND $Upper\:\:Confidence\:\:Limit \lt 0$:
the confidence interval does not contain $0$
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of the alternative hypothesis
Interpretation: The population proportion for the first sample is significantly less than the
population proportion for the second sample
Condition $2$
If $Lower\:\:Confidence\:\:Limit \lt 0$ AND $Upper\:\:Confidence\:\:Limit \gt 0$:
the confidence interval contains $0$
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of the alternative hypothesis
Interpretation: The population proportion for the first sample is NOT significantly less than the
population proportion for the second sample
Construct a confidence interval using: $CL = 1 - \alpha$
Determine the confidence interval using an appropriate confidence level
Condition $1$
If $Lower\:\:Confidence\:\:Limit \gt 0$ AND $Upper\:\:Confidence\:\:Limit \gt 0$:
the confidence interval does not contain $0$
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of the alternative hypothesis
Interpretation: The population proportion for the first sample is significantly more than the
population proportion for the second sample
Condition $2$
If $Lower\:\:Confidence\:\:Limit \lt 0$ AND $Upper\:\:Confidence\:\:Limit \gt 0$:
the confidence interval contains $0$
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of the alternative hypothesis
Interpretation: The population proportion for the first sample is NOT significantly more than the
population proportion for the second sample
Construct a confidence interval using: $CL = 1 - \alpha$
Determine the confidence interval using an appropriate confidence level
Condition $1$
If $Lower\:\:Confidence\:\:Limit \lt 0$ AND $Upper\:\:Confidence\:\:Limit \lt 0$ OR
$Lower\:\:Confidence\:\:Limit \gt 0$ AND $Upper\:\:Confidence\:\:Limit \gt 0$
the confidence interval does not contain $0$
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to warrant the rejection of the null hypothesis
Interpretation: The population proportion for the first sample is significantly different from the
population proportion for the second sample
Condition $2$
If $Lower\:\:Confidence\:\:Limit \lt 0$ AND $Upper\:\:Confidence\:\:Limit \gt 0$:
the confidence interval contains $0$
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to warrant the rejection of the null hypothesis
Interpretation: The population proportion for the first sample is NOT significantly different from the
population proportion for the second sample
Calculate the Pearson correlation coefficient
Calculate the critical value of the Pearson correlation coefficient
Condition $1$
If $r \lt 0$ AND $r \lt Critical\:\:value\:\:of\:\:r$:
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of a negative linear correlation
Condition $2$
If $r \lt 0$ AND $r \gt Critical\:\:value\:\:of\:\:r$:
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of a negative linear correlation
Calculate the Pearson correlation coefficient
Calculate the critical value of the Pearson correlation coefficient
Condition $1$
If $r \gt 0$ AND $r \gt Critical\:\:value\:\:of\:\:r$:
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of a positive linear correlation
Condition $2$
If $r \gt 0$ AND $r \lt Critical\:\:value\:\:of\:\:r$:
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of a positive linear correlation
Calculate the Pearson correlation coefficient
Calculate the critical value of the Pearson correlation coefficient
Condition $1$
If $|r| \gt Critical\:\:value\:\:of\:\:r$:
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of a linear correlation
Condition $2$
If $|r| \le Critical\:\:value\:\:of\:\:r$:
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of a linear correlation
Calculate the Pearson correlation coefficient
Calculate the test statistic
Determine the probability value (p-value) of the test statistic
Condition $1$
If $r \lt 0$ AND $P-value \le \alpha$:
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of a negative linear correlation
Condition $2$
If $r \lt 0$ AND $P-value \gt \alpha$:
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of a negative linear correlation
Calculate the Pearson correlation coefficient
Calculate the test statistic
Determine the probability value (p-value) of the test statistic
Condition $1$
If $r \gt 0$ AND $P-value \le \alpha$:
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of a positive linear correlation
Condition $2$
If $r \gt 0$ AND $P-value \gt \alpha$:
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of a positive linear correlation
Calculate the Pearson correlation coefficient
Calculate the test statistic
Determine the probability value (p-value) of the test statistic
Condition $1$
If $P-value \le \alpha$:
Decision: Reject the null hypothesis
Conclusion: There is sufficient evidence to support the claim of a linear correlation
Condition $2$
If $P-value \gt \alpha$:
Decision: Do not reject the null hypothesis
Conclusion: There is insufficient evidence to support the claim of a linear correlation
Confidence Level (Percent) | 1% | 5% | 10% | 90% | 95% | 99% | ||
Confidence Level (Decimal) | 0.01 | 0.05 | 0.1 | 0.9 | 0.95 | 0.99 | ||
OR | ||||||||
Significance Level (Percent) | 99% | 95% | 90% | 10% | 5% | 1% | ||
Significance Level (Decimal) | 0.99 | 0.95 | 0.9 | 0.1 | 0.05 | 0.01 | ||
Critical
Values $\rightarrow$ Degrees of Freedom $\downarrow$ |
Lower-tail Critical Values | Upper-tail Critical Values | ||||||
---|---|---|---|---|---|---|---|---|
1 | 0.00016 | 0.00393 | 0.01579 | 2.70554 | 3.84146 | 6.63490 | ||
2 | 0.02010 | 0.10259 | 0.21072 | 4.60517 | 5.99146 | 9.21034 | ||
3 | 0.11483 | 0.35185 | 0.58437 | 6.25139 | 7.81473 | 11.34487 | ||
4 | 0.29711 | 0.71072 | 1.06362 | 7.77944 | 9.48773 | 13.27670 |
z test:
OR
t test: