I greet you this day,
First: Read the Stories (Yes, I tell stories too. ☺)
The stories will introduce you to the topic, while making you smile/laugh at the same time.
Second: Review the Notes.
Third: View the Videos.
Fourth: Solve the questions/solved examples.
Fifth: Check your solutions with my thoroughly-explained solved examples.
Sixth: Check your answers with the calculators.
I wrote some of the codes for the calculators using Javascript, a client-side scripting language. In
addition, I used the AJAX Javascript library. Please use the latest Internet browsers.
The calculators should work.
Comments, ideas, areas of improvement, questions, and constructive criticisms are welcome. Should you
need to contact me, please use the form at the bottom of the page. Thank you for visiting.
Samuel Chukwuemeka (Samdom For Peace)
B.Eng., A.A.T, M.Ed., M.S
Please check back later for the story.
Students will:
(1.) Discuss Inferential Statistics.
(2.) Estimate population proportion.
(3.) Estimate population mean.
(4.) Estimate population variance.
(5.) Estimate population standard deviation.
(6.) Calculate inferential statistics using an appropriate statistical software package such as R studio.
(7.) Draw statistical inferences from a large, realistic data set using a statistical software package such as R studio.
(8.) Solve applied problems in inferential statistics.
Do you have any favorite News Media? Or do you think any/some of them are fake news?
(Lol ...I did not mention any name so I do not get in trouble. 😊 But anyway, let's get back on track. Please note: I am not endorsing any of them. I am only using them to teach you topics in Statistics.)
Let us review some of the results of the surveys/polls conducted by these New Media. No worries, I shall avoid controversial topics.
1st Example: Using Sample Proportion to Estimate Population Proportion
Proportion deals with Fraction which deals with Percentage.
Notice the result of the poll: Poll: Seven in 10 Americans say TikTok is a threat to national security.
Keep in mind that 7 in 10 Americans means 70% of Americans.
But come on, do you think NPR/PBS NewsHour/Marist Poll surveyed all American adults?
If they did not survey all American adults, why would they say 7 in 10 Americans?
By the way, this is the data collection process:
So, would it not be better if they specified: 70% of 1327 = 0.7(1327) = 928.9 ≈ 929 adults...the 70% here is a statistic (numerical summary of a sample)
But they specified 70% of American adults ... the 70% here is a parameter (numerical summary of a population)
Noticed how NPR/PBS NewsHour/Marist Poll used the results of a sample to infer on a population?
Notice they included: the result of the poll, the sample size, and the margin of error.
But they did not specify an important measure. We shall find out that measure in the second example.
Let us review another example.
2nd Example: Using Sample Mean to Estimate Population Mean
Mean is the same as Average.
The sample mean is a useful estimator for the population mean because the sample mean is accurate and, with a sufficiently large sample size, very precise.
The spread of the distribution of the sample mean is much smaller than the spread of the population.
As the sample size increases, the spread of the sample mean decreases.
The accuracy of the sample mean in estimating the population mean is measured by the bias.
Bias is the mean distance between the sample statistic and the parameter it is estimating.
Let us discuss an example on how the sample mean is used to estimate the population mean.
The result of the survey states that: Americans are spending 4 hours, 25 minutes each day on their phones.
They only surveyed 1000 Americans.
They did not mention: average... but they should have mentioned it.
Why would they not write: 1000 Americans are spending an average of 4 hours, 25 minutes each day on their phones?
But, rather they used the results of a sample of Americans to make a generalization about the population of Americans.
Though they missed the wording: average in the conclusion, they did not omit an important measure: the confidence level
They included the result of the survey, the sample size, and the margin of error, and the confidence level.
Please note: This is a learning process, not an avenue to criticize reports.
Some of you may be journalists and may report polls/surveys. Please make sure you do not omit any necessary measure.
Welcome to Inferential Statistics.
In statistical inference, measurements are made on a sample and generalizations are made to a population.
It is often difficult to measure the population, hence we measure samples.
The results are then generalized to the population.
$ (1.)\;\; \alpha = 1 - CL ...in\;\;decimal \\[5ex] (2.)\:\: \hat{p} = \dfrac{x}{n} \\[5ex] (3.)\:\: \hat{p} + \hat{q} = 1 \\[5ex] (4.)\;\; \hat{p} = \dfrac{UCL + LCL}{2} \\[5ex] (5.)\;\; E = \dfrac{UCL - LCL}{2} \\[5ex] (6.)\:\: E = z_{\dfrac{\alpha}{2}} * \sqrt{\dfrac{\hat{p} * \hat{q}}{n}} \\[7ex] (7.)\;\; n = \dfrac{0.25 * \left(z_{\dfrac{\alpha}{2}}\right)^2}{E^2} \\[7ex] $
Significance Level, α | Confidence Level, CL | critical z value separating an area or probability of $\dfrac{\alpha}{2}$ in the right tail, $z_{\dfrac{\alpha}{2}}$ |
---|---|---|
1% (0.01) | 99% (0.99) | 2.575829306443923 ≈ 2.576 |
5% (0.05) | 95% (0.95) | 1.9599639861189817 ≈ 1.96 |
10% (0.1) | 90% (0.9) | 1.6448536251332162 ≈ 1.64 |
$ (1.)\;\; \alpha = 1 - CL ...in\;\;decimal \\[5ex] (2.)\;\; LCI = UCL - LCL \\[5ex] (3.)\:\: \bar{x} = \dfrac{\Sigma x}{n} \\[7ex] (4.)\:\: \bar{x} = \dfrac{UCL + LCL}{2} \\[7ex] (5.)\;\; E = \dfrac{UCL - LCL}{2} \\[7ex] (6.)\;\; LCI = 2E \\[5ex] (7.)\;\; SE = \dfrac{\sigma}{\sqrt{n}} \\[7ex] (8.)\:\: E = \dfrac{\sigma * z_{\dfrac{\alpha}{2}}}{\sqrt{n}} \\[10ex] (9.)\;\; E = \dfrac{s * t_{\dfrac{\alpha}{2}}}{\sqrt{n}} \\[10ex] (10.)\;\; n = \left(\dfrac{\sigma * z_{\dfrac{\alpha}{2}}}{E}\right)^2 \\[10ex] (11.)\;\; n = \left(\dfrac{s * t_{\dfrac{\alpha}{2}}}{E}\right)^2 \\[10ex] $
Significance Level, α | Confidence Level, CL | critical z value separating an area or probability of $\dfrac{\alpha}{2}$ in the right tail, $z_{\dfrac{\alpha}{2}}$ |
---|---|---|
1% (0.01) | 99% (0.99) | 2.575829306443923 ≈ 2.576 |
5% (0.05) | 95% (0.95) | 1.9599639861189817 ≈ 1.96 |
10% (0.1) | 90% (0.9) | 1.6448536251332162 ≈ 1.64 |
Standard Normal Distribution Table (Left-Shaded Area)
Standard Normal Distribution Table (Center-Shaded Area)
By default, the area is to the left.
In other words, the result from the TI-calculator shown below gives the critical t-value such that the area is in the left tail.
The value given by the calculator is a negative value by default.
Based on the diagrams in t Distribution Table (Third) table:
To determine the critical t-value if the:
(1.) Area is to the right, subtract the area in the left tail from 1 (because the total area under the curve is 1)
Then, use the value.
(2.) Area is in both tails, use both the value (negative value) and the absolute value (positive value).
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